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Code Geeks Blog | Code Madness
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Code Geeks Blog | Code Madness
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SPOJ : DIVSUM (Divisor Summation) | Code Geeks Blog
Divisor Summation (DIVSUM) The core logic for solving this question is that divisors always exist in pairs. So, for a number 't', if 'i' is a divisor then 't/i' is also a divisor. And the smaller numb...
Contest SCC040913 : Question-1 Editorial | Code Geeks Blog
Question 1.) Given two number a and b.Count how many numbers in the range a to b(including both a and b) has odd number of divisors. Input First line of input contains number of test cases T.Each of t...